Nope. You pay per segment. The segment is equal or less than 64MiB, so it should use 8-9 segments (overhead on erasure coding and encryption). I would say that using 64MiB part size could use more segments (because there is also overhead on erasure coding after encryption). Roughly 1 more segment after all 64MiB of data (so actually you need to use something about 60MiB of data before encryption and erasure coding). For the 512MiB chunk size there likely would be only one additional segment.
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